Neogeography

View A Great Way to Spend a Night in Hollywood in a larger map
     Neogeography allows ordinary people to access maps created by others like themselves via the World Wide Web. It can either be extremely useful or completely useless; it all depends upon how knowledgeable the author of the map is. If the map has been created by someone very familiar with the area being mapped, then it will most likely be a trustworthy and useful form of navigation. However, if the map has been produced by someone unfamiliar with the subject, then it will most likely be a very poor representation of the area and will not be able to be used for accurate navigation. It is extremely important to make sure the author of the map is a trustworthy source who seems to be very well-informed about the area being mapped. This will insure that your map is in fact accurate.
     I created the map above, “A Great Way to Spend a Night in Hollywood”, because the area I chose to map is one in which I’m very familiar with. I knew the exact location of every point, polygon, and line I chose to include on the map, so I was certain I’d be able to provide the reader with an accurate representation of that area of Hollywood. I’m also knowledgeable on each of the entities included on the map, so I knew I’d be able to provide the reader with accurate geotags.

USGS Topographic Maps

1. Beverly Hills Quadrangle
2. Canoga Park Quadrangle, Van Nuys Quadrangle, Burbank Quadrangle, Topanga Quadrangle, Hollywood Quadrangle, Venice Quadrangle, and Inglewood Quadrangle
3. 1966
4. National Geodetic Vertical Datum of 1929, North American Datum of 1927 (NAD 27), and North American Datum of 1983 (NAD 83)
5. 1:24,000
6.
a) 1:24,000
   (1:24,000)5
     5 cm:120,000 cm
     100 cm in 1 m, so 5/100:120,000/100
    .05 m:1200 m
     5 cm on the map is equivalent to 1200 m on the ground
b) 1:24,000
   (1:24,000)5
    5 in:120,000 in
    63,360 in in 1 mi, so 5/63,360:120,000/63,360
   .0000789 mi:1.894 mi
    5 in on the map is equivalent to 1.894 mi on the ground
c) 1:24,000
    x:1 mi
    x:63,360 in
    x = 63,360in/24,000
    x = 2.64 in
    2.64:63,360
    1 mi on the ground is equivalent to 2.64 in on the map
d) 1:24,000
   (1:24,000)3
    3:72,000
    3km:72,000km
    x:3 km
    3 km = 300,000 cm
    x = 300,000cm/72,000
    x = 4.17 cm
    3 km on the ground is equivalent to 4.17 cm on the map
7. 20 ft
8.
a) 34°04'30" N 118°26'15" W
    34+.067+.008   118+.43+.004
    N 34.0678° W 118.434°
b) 34°00'25" N 118°29'50" W
    34+.00+.007   118+.48+.014
    N 34.007 W 118.494
c) 34°7'25" N 118°24'30" W
    34+.17+.007   118+.4+.008
    N 34.177° W 118.408°
9.
a) 560 ft
    1 m = 3.2808399 ft
    560 ft/3.2808399
    171 m
b) 140 ft
    140 ft/3.2808399
    43 m
c) 620 ft
    620 ft/3.2808399
    189 m
10. 11
11. 3763, 362
12. 10,000 ft x 10,000 ft = 100,000,000 sq ft
      100,000,000 sq ft/3.2808399
      30,480,000 sq m
13.

14. Difference between the geographic north pole at 0°48' E and the magnetic north pole at 14° E
      Magnetic declination = 13°12' E
15. The stream is flowing south
16.